Thank you for your reply.
My Inverter is configured in SBU mode, but Im guessing the same rule that you mentioned applies in this mode too, correct? I'm aware of the No load power consumption, but I thought this can also be powered by the 220V AC grid voltage, not only by the batteries. I'm guessing there is no way to make it run from the grid, instead of the batteries, right? Also, have you tried turning on the option for power saving when there is no load? I'm guessing this current goes to 0 in this case?
I have 10.5 Kwh batteries. I did not make any precise math for the amps over the night but from my point of view, its depleting more than 10% over 10 hours. Which is 1050 Wh, divided by 48 volts results 21 Amps which is double than the expected current consumption. (I will monitor the current consumption more precisely so I make sure I do not get anything wrong).
Taking the 0.9 Amps per hour, this should mean 9 A for 10 hours, which is 432 Watts (48V * 9A). 432 Watts should only be 4% from my 10.5 Kwh batteries... which is reasonable, but I think mine takes much more.
I`m familiar with Grafana but how did you monitor the instant current consumption?
Thanks in advance for your input!